Leetcode 7. Reverse Integer 题解

class Solution {
public:
    int reverse(int x) {
        std::vector<int> digits;
        while (x != 0)
        {
            digits.push_back(x%10);
            x = x/10;
        }
        int res = 0;
        for (size_t i = 0; i < digits.size(); ++i )
        {
            if(abs(res) > INT_MAX / 10)
                return 0;
            else
                res = res * 10 + digits[i];
        }
        return res;
    }
};